I just think some of the justification points are a little questionable, hence I am questioning them. obviously getting way to hot, no gearbox seal issues or anything else. My old Sud's discs were permanently blue when I sold it. although Sud racers do not have any problems. Fair enough and for serious tracking the heat location problem is an issue. penny has just dropped, you are selling/marketing a kit. With tilted arms there must be a reaction force in the pushrod which pushes the car body up.Click to expand.Nothing to do with the location, but better quality parts. Important here is the force going over the suspension arms. The difference to the "anti model" is that we take a closer look at the suspension and try to figure out how it is compressed. By this we get trough a static analysies the external forces acting on the car and no incluence of the torque on the diff. So when you think about the torque on the chassis we can assume a model of suspension/chassis as a rigid body. It is just required to make the system stiff but it does not increase tilting of the chassis. The torque acting on the diff/chassis is nothing else than an internal load. I guess that is what you where heading to? With this we would end up with twice the amount of dive so this simply can't be true. So those two torques would tilt the chassis down + the mass of the car. Just in one case it goes over the axle and in the other over the suspension. There will also be torque acting on the front of the chassis because it doesn't matter if the brakes are inboard or outboard because in both cases torque is reacted to the chassis. When I follow your way of thinking there will be torque acting on the rear of the chassis (inboard brakes) trying to rotate it so that the front dives down. I wonder why nobody else tries to answer the question. I must say once again I am a bit disappointed by the forum. What happens with the torque once it is reacted into the chassis? I made some pencil drawing but it didn't turned out to be nice.Ĭaito wrote:As the you brake the caliper and disc get opposing forces which cancel out, but you get torque on the driveshaft and torque on the chassis. In first case both is carried by the suspension arms in second case just the force has to be carried while the torque gets carried by the axle. So what happens is a split of torque and the force causing the difference. This force will be transmitted by the central bearing to the upright and into the suspension arms. Also when there are no outboard brakes there is no connection between rim and upright which can transmit torque so there is only the braking force left which has to be carried. When the brakes are inboard there will be an axle running from the diff to the rim which transmits the torque to the chassis. So the braking force and the torque will be transmitted over the upright into the suspension arms. When the brakes are outboard the tire and the upright are rigidly fixed together trough the brake pad/disc and can be considered as a solid part (more or less). Nice question, you got me thinking for a couple minutes. Is this right?Īnyway, supposing what I said is correct, I still can't get why with inboard brakes the brake force is applied at the wheel centerline. This force would cancel up with one in the caliper giving a net moment at the chassis, halfway between the calipper and the center of the disc. The force at the disc can be imagined as a torque and a force on the center of the disc. Now we have a similar situation with inboard brakes:Īs brakes are applied you get a force pointing down on the disc, and one pointing up in the caliper. That torque would be clockwise as seen in the image. Still, as you said, I have that torque in the hub which I wouldn't if the brakes where inboard. The force going down to the wheel transfers to the bearings, to the hub and it's cancelled with the one for the caliper. Which could be seen as a force down and a torque in the upright. This could be seen as a force down, plus a torque in the wheel. When you brake the caliper generate a force going down. If we imagine the car going to the right. But as I see it, those forces are internal and should cancel out.
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